Ajit Athle submitted this problem, as it neatly fits in our series on Equilateral Triangles. He said:
"Here's a simple problem to go in your current series on ET's. In equilateral triangle ABC, we've cevians BD (D on AC) & CE (E on AB) such that 2*BE = AE & 2*AD = DC. If CE & BD intersect in P, then prove, w/o using trig! onometry or co-ordinate geometry, that AP is perpendicular to CE."
Thank you Ajit!
Thank you Ajit!
Problems on Co-ordinate Geometry
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